Analog Signal Conditioning for Accurate Measurements

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Analog = Signal=20 Conditioning for Accurate Measurements =

Reference=20 Number: AA-00615 Views: = 1181 Created: 10/29/2014 = 11:18=20 am Last Updated: 10/29/2014 = 05:30=20 pm

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Q: Should I put some sort of circuit between = my=20 sensor and an analog-to-digital = converter?

A: Yes. You probably need some signal = conditioning.=20 The explanation below goes on for a bit, but stay with it and = you'll=20 understand what you need and why you need it.

Before you make any connections, get the electrical = specifications for the analog-to-digital converter = (ADC) and=20 for the sensor or sensors in your = system. Let's=20 assume the data-acquisition module uses a Maxim = Integrated=20 Products MAX197 12-bit ADC. This device can accept = eight=20 differential (2-wire) inputs or 16 single-ended = (1-wire)=20 inputs. Maxim's specifications show an input impedance of 21 kohms for = single-ended=20 inputs and 16 kohms for differential inputs.

Now let's assume your system uses an Analog Devices AD590 = temperature sensor in a simple circuit = (Figure=20 1) to produces a 1-mV/K output. The sensor serves as a variable- = current=20 source that passes 1 =C2=B5A per Kelvin (K), or per = degree Celsius=20 (=C2=B0C). The Kelvin scale uses the same increments = as the Celsius=20 scale, but it starts at absolute zero: 0K or = -273=C2=B0C. At 0=C2=B0C,=20 the Kelvin scale reads 273K and at 25=C2=B0C it reads = 298K. The=20 Kelvin symbol does not include a degree mark. (For a=20 temperature-scale comparison, visit: http://www.magnet.fsu.edu/education/tutorials/magnetminut= e/kelvin-transcript.html.)

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Figure 1. The current from this AD590 = sensor passes through a = precision=20 1000-ohm resistor. The resulting = voltage represents temperature = at a rate=20 of 1 mV/K. So at 20=C2=B0C (293K), you would measure = 293 mV at the=20 circuit output.

Now what happens when you connect the AD590 to a=20 single-ended input on the MAX197 ADC (Figure = 2)? Note=20 this arrangement places the 1000-ohm resistor at the sensor in parallel with the = ADC's input=20 resistance; 21,000 ohms.

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Figure 2. The connection of an AD590 = sensor and MAC197 ADC creates a = circuit=20 with two resistances in parallel.

Could the ADC input resistance affect temperature = readings?=20 Ohm's Law lets us calculate the equivalent resistance for these two = resistors:

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As a result, the complete circuit looks like that = shown in=20 Figure 3. If a 1000-ohm resistor provides a 293 mV = output for a=20 20=C2=B0C temperature, what happens when the circuit = has a 955-ohm=20 resistor instead?

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Figure 3. The equivalent circuit for the = AD590=20 sensor and the MAX197 ADC.

Once again, Ohm's Law lets us calculate the = voltage from the known current = through=20 the sensor and the parallel = resistance. At 293K, the AD590 = passes 293=20 =C2=B5A, but with the 955-ohm resistor, what voltage goes to the ADC = input?

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The voltage output does not match = what we=20 expected. In other words, the input impedance of the ADC will cause = an=20 8-Kelvin error in the ADC reading. So you should not = connect=20 the AD590 sensor-circuit output directly to a MAX197=20 input.

Keep in mind the AD590 controls the small current = flow and=20 it--not the 1000-ohm resistor--creates a = high-impedance=20 output.

Q: So how do I overcome this impedance problem?

A: You need an amplifier with a = low-impedance, or=20 low-resistance, output that will provide sufficient = current so=20 the ADC input resistance does not affect the=20 amplifier's output signal. In other words, if the = amplifier=20 produces a 2.20-volt output, for example, the = 21,000-ohm input=20 resistance of the MAX197 ADC = should not=20 affect the 2.20-volt signal. (Or if a slight = difference=20 occurs, it should be small enough that the ADC will = not detect=20 it.)

The data sheet for the AD590 sensor includes a circuit that = uses an=20 OP177 operational amplifier (op amp) to boost the sensor signal (Figure = 4). The=20 OP177 circuit produces a 100-mV/=C2=B0C, or 100-mV/K, = signal. The=20 OP177 data sheet lists a typical open-loop output = resistance of 60 ohms. This = resistance in parallel with the = 21,000-ohm input resistance of the MAX197 ADC = yields a=20 combined resistance of 59.8 ohms--a = change of less=20 than one percent.

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Figure 4. Example circuit for an AD590 = sensor that uses an OP177 = operational=20 amplifier (op amp) to provide higher voltages = to an ADC=20 or other measurement circuit. (Courtesy of Analog Devices.)

If an op-amp data sheet lacks output-resistance=20 information, you can perform an experiment to = determine it.=20 Let's assume an op amp produces a 2.20-volt output = with=20 nothing connected to the output--an open circuit. = Place a=20 100-ohm precision resistor between the output and = ground (Figure 5) and = measure the=20 op-amp output voltage and the current through = the=20 resistor. You can use a = different=20 resistance value if you wish. = Caution:=20 Use a digital meter with a high input = impedance or the meter itself = will alter=20 the measurements.

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Figure 5. Test circuit for an op-amp output = impedance, or resistance. In this circuit the = non-inverting op-amp configuration amplifies the = 1.10-volt=20 signal by two.

Say the voltage drops from 2.20 volts = to 2.17=20 volts for a current of 20 mA (0.02A) through the = 100-ohm=20 resistor. Use Ohm's Law to = calculate the=20 op-amp's output resistance. You know the = current from the=20 op-amp's output and you know the voltage difference between an=20 open-circuit and a loaded-circuit condition:

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That's a sufficiently low output impedance that the ADC input = resistance will not load the = amplifier=20 enough to alter the 2.21-volt output.

To learn more about op amps I recommend the book, = "Op Amps for Everyone," by Bruce = Carter and=20 Ron Mancini. Elsevier-Newnes, 2013. ISBN-13: = 978-0123914958.=20 You can find a lot of useful information on the = Internet,=20 too.

Q: What if I don't have the time or = experience to=20 build and test op-amp circuits?

A: Use an instrumentation amplifier instead. = This=20 type of amplifier, often called an "in amp" or INA, provides a "gain = block" that=20 simplifies connections between sensors and ADCs. The = INA827=20 amplifier from Texas Instruments provides a good = example. One=20 external resistor sets the gain or = amplification=20 factor. Op-amps on the other hand, require several = carefully=20 matched resistances. The INA827 offers amplification = factors=20 of five and as high as 100. Companies such as Analog Devices, Linear = Technology,=20 Microchip Technology, and Texas Instruments sell many = types of=20 in-amp integrated circuits (ICs), which make it easy = to design=20 and construct an in-amp "front end" = signal-conditioning=20 circuit for your ADC.

Unfortunately, only a few companies sell in-amp = modules=20 that let you set the gain with an external resistor you select. Most = commercial=20 in-amp modules offer only preset gains of, say, 1, 10, = 100 and=20 1000. These modules also constrain input voltages to a = preset=20 range and produce an output voltage within a preset range. = In other=20 words, they don't offer much flexibility. For examples = of=20 modules that provide more flexibility, visit Omega Engineering or Ocean Controls (Australia).

If you decide to design and build an in-amp = circuit, the=20 evaluation boards and modules available from the = in-amp IC=20 manufacturers let you experiment with the ICs in = working=20 circuits. Digikey lists 13 in-amp evaluation = boards,=20 most for under $100. If you decide to use an in-amp = IC, I=20 might choose a prototype board that fits in a = DIN-compatible=20 enclosure. The "Electronics Salon" eBay store = sells several=20 such boards and housings that clip onto a standard DIN = rail=20 used in industrial-control equipment.

Q: Does an instrumentation amplifier offer=20 advantages over an op amp?

A: Yes. In addition to using only one = resistor to set the gain, or=20 amplification factor, in-amps have a high input = impedance, so they don't affect = signals=20 from high-impedance sensors such as an AD590. In amps = also=20 have a high common-mode AC/DC rejection ratio (CMRR). = That=20 means a signal common to both the positive and = negative=20 amplifier inputs gets greatly attenuated before it = reaches the=20 in-amp output. The INA827 in amp has an 88 dB CMRR for DC = signals. The=20 CMRR in amplifiers decreases at the frequency of input = signals=20 increases. An in-amp can remove common-mode AC signals = such as=20 60- or 50-Hz electrical noise caused by nearby = equipment. For=20 more information about CMRR, visit: http://en.wikipedia.org/wiki/Common-mode_rejection_ratio<= /A>.

The circuit in Figure 6 illustrates an in = amp connected in a bridge = circuit that=20 could measure strain, pressure, humidity, or another = physical=20 phenomena with a resistive sensor substituted for the Rs = component.=20 One side of the bridge connects to the in-amp positive = input=20 and the other side connects to the in-amp negative = input. To=20 start, assume all resistors in the bridge have the = same=20 value.

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Figure 6. This bridge circuit indicates a = resistance change in the = sensor element (Rs) as a = voltage difference between the = two output=20 signals applied to the in amp. The amplifier removes any=20 common-mode voltage from the excitation = source and=20 puts out only the voltage difference between the = two=20 inputs. Resistor Rg determines the = in-amp's=20 gain.

As the sensor's resistance changes, the bridge = circuit=20 produces a small voltage difference = between the two=20 connections to the in amp. Both inputs also receive a = part of=20 the bridge's excitation voltage, say +3 = volts. Thus,=20 in this example the in-amp minus input "sees," a = 2.000V=20 signal, while the positive input "sees" 2.015V. The = 0.015V=20 difference between the two inputs provides the useful = sensor information. Note that = the in-amp=20 circuit converted a differential signal to a=20 single-ended signal referenced to ground. In-amps have a = reference=20 input, so if necessary you can offset the in-amp's = output.=20 I'll talk more about amplification and offset in my = next=20 column.

For more information about in amps, I recommend the = following:

"A Designer's Guide to = Instrumentation=20 Amplifiers," 3rd edition, Analog Devices
"Getting the Most out of Your = Instrumentation=20 Amplifier Design," Texas Instruments
"Ultra-precise Instrumentation = Amplifier Makes=20 Robust Thermocouple Interface," = (PDF)=20 Design Note 302, Linear Technology.

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{link:clear}{link:close}

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Computing/HM= I=20 COM= =20 Express Industrial=20 Computers H= MI=20 Computers E= mbedded=20 RISC	Serial=20 As= ynchronous=20 Serial Syn= chronous=20 Serial MIL-STD-1= 553	I/O=20 Distribut= ed=20 I/O Remote=20 I/O Digital=20 I/O Analog=20 I/O	Accessories=20 = Computer=20 Storage Industrial=20 Computer Memory Cables= SeaRAQ= =20 I/O = SeaI/O=20 Expansion	Po= wer=20 Supplies T= erminal=20 Blocks Adapters=20 & Converters Relay=20 Racks & Relays Mounting=20 Hardware	= PC/104=20 Portholes Hubs=20 & Switches = Books=20 & References Software=

Support=20 M= anuals=20 Software=20 Drivers=20 Product=20 Literature=20 FAQs=20 Resource=20 Center	Custom=20 Solutions Case = Studies Design=20 Center Custom = Capabilities Company Our = Story Careers	Community Tom's=20 Trivia Video=20 Channel Blog Twitter	News=20 & Events Press=20 Releases Events <= A=20 href=3D_http_/www.sealevel.com/company/news/_.html>Media = Kit	Email = Signup=20 Be the first to know. Keep up-to-date = on the=20 latest Sealevel happenings by subscribing to our monthly newsletter. =	Contact 864.843.4= 343=20 tel 864.843.3067 fax support@sealevel.com sales@sealevel.com Sales = &=20 Privacy = Policies

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